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Re: Introduction to Doug's RSt (4)

Posted on Wednesday, June 10, 2020 at 07:04AM by Registered CommenterDoug | CommentsPost a Comment

by dbundy » Thu Jul 13, 2017 12:41 pm

Sun wrote:
Hello Doug,
Thank you for your presentation.
Let me use a notation of a-c-b for my own convenient to represent your equation.
Am i correct that you assume everything starts from one net displacement, 1/2 and 2/1? Particles are consequences that combine variable numbers of 1/2 and 2/1 with variable numbers of 1/1? 1/1 represent for unit motion? a, c, b stand for the each dimension of motion?
How did you get 2S|T = 2/4 + 2/1 + 2/1? Why it is not S|T+SUDR=1/2+1/1+2/1+2/1?
The basic S|T equation, S|T = 1/2 + 1/1 + 2/1 = 4|4 num, expresses the total scalar motion of the SUDR (s/ t = 1/2) and TUDR (s/t = 2/1) combination. The middle term (1/1) consists of the inner portion of the SUDR oscillation (the numerator) and the inner portion of the TUDR oscillation (the denominator.) Without it the total of natural units of motion (num), would be incorrect.

The ratio of SUDRs to TUDRs (Ss and Ts) in this equation is 1:1, or balanced. We can unbalance it in two “directions,” by adding an S or a T to the equation. Adding an S, S|T + S, gives us 2S|T. Adding a T, gives us S|2T.

2S|T = (1/2 + 1/2)|2/1 = 2/4|2/1.

In it’s expanded form, this is ((1/2) + (1/2)) + 1/1+ 2/1 = 2/4 + 2/1 + 2/1 = 6|6 num, showing how the additional S unit changes the balanced middle term (1/1) of S|T to the unbalanced middle term (2/1) of 2S|T.

I hope that make more sense now. This new math is a little tricky, because not only do we add numerators to numerators and denominators to denominators, but we CONSTRUCT the middle term from the LH (numerator) and the RH (denominator) terms, after the fact so-to-speak.

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